From the information they provide:
Where did you find that info? Or are you extrapolating from the addresses?
When I migrated to Zen last year they were still not enabling IPv6 by default, that info was in the reply to me requesting it to be enabled.
Zen describe the PD as LAN and ND as WAN. So I need to add the longer ND /64 address to my DNS?
The /48 PD is simply a routed block of addresses which can be obtained by the router with DHCPv6-PD.
The /64 ND is used to construct the globally unique WAN address. The underlying mechanisms for IPv6 addressing are different to IPv4, there is no ARP or DHCP-provided gateway - instead there is Neighbour Discovery (ND) which comprises a number of ICMPv6 message types, the important ones in this case are Router Solicitation (RS) and Router Advertisment (RA).
The RA message from the ISP provides the /64 network (as shown in the email or control panel), this is combined with a subnet address from the router to generate the 128-bit address. There are plenty of articles on SLAAC and converting EUI-48 MAC addresses to EUI-64 to form the subnet part of the address.
For example, with a PD of 2001:DB8:A1B2:C3D4::/64 and a WAN port MAC address of 00:11:22:33:44:55 the IPv6 address would be 2001:DB8:A1B2:C3D4:211:22FF:FE33:4455 - this would be what you add to DNS as an AAAA record for the router itself.